Code:
--------------------------------------------------------------------------- srand(time|$$);
$random_number = int(rand(10000000));
$temp_file = $data_directory . "ureserve" . $random_number . ".tmp";
if (!(open(TEMP_DATA_FILE, ">" . $temp_file)))
{
&return_error("File Error","Unable to open " . $temp_file);
}
--------------------------------------------
getting error on the open statement, not able to understand..pls anyone can help me to resolve it.
Thanks in Advance,
OAUser.
Unable to open error