# We are processing the form.
if ((keys %in != 0) && (!$in{'product'})) {
&process_form;
}
Apr 16, 1999, 1:06 PM
Novice (9 posts)
Apr 16, 1999, 1:06 PM
Post #2 of 6
Views: 4384
If the hash %in has something/anything in it, and the value associated with the product line in the %in hash exists, then run subroutine process_form...
Unless I misread it. :-)
------------------
Charles Capps
solareclipse.net/
[This message has been edited by Charles Capps (edited April 16, 1999).]
Unless I misread it. :-)
------------------
Charles Capps
solareclipse.net/
[This message has been edited by Charles Capps (edited April 16, 1999).]
Apr 16, 1999, 10:44 PM
Novice (9 posts)
Apr 16, 1999, 10:44 PM
Post #4 of 6
Views: 4413
Ah, right. :-)
Apr 16, 1999, 10:56 PM
Veteran (3111 posts)
Apr 16, 1999, 10:56 PM
Post #5 of 6
Views: 4394
For some reason, something in the back of my head keeps telling me that the code should be written as:
&process_form;
}
I think the "!=0" part isn't really needed but it doesn't hurt. It could also be written as (someone correct me if I am wrong):
Code:
if ((keys %in) && (!$in{'product'})) { &process_form;
}
I think the "!=0" part isn't really needed but it doesn't hurt. It could also be written as (someone correct me if I am wrong):
Code:
((keys %in) and (!$in{'product'}) and &process_form);
Apr 17, 1999, 9:35 AM
Veteran (3111 posts)
Apr 17, 1999, 9:35 AM
Post #6 of 6
Views: 4392
Charles,
I think you are correct on the first part, but the "(!$in{'product'})" is checking to see if the product does not exist (note the ! before the $). So if the hash %in is not empty but there is no product, then process the form.
I think you are correct on the first part, but the "(!$in{'product'})" is checking to see if the product does not exist (note the ! before the $). So if the hash %in is not empty but there is no product, then process the form.