im using a line of code i was giving. its suppost to get the local time and assign it to a scalar which is then added to a database. the problem is that the time returned 1970-01-01 00:00:00, which i think is the default, and im not sure what im doing wrong.

$time = HTTP::Date::time2iso(localtime(time()));

thanks
Pedge

If you want localtime as a scalar then use:

my $date = scalar localtime();

originally the problem was that the date was added into the database but the days and month were one digit out because perl starts at 0 not 1. which is why someone suggested i use time2iso.

Pedge

I'm not really sure what you mean, "perl" doesn't start at 0, arrays do though :)

Using the code I suggested above will return the correct date, if it didn't it would be a useless function :)

when i added date to a sessions database, december would be month 11 and January would be 00. which is why im trying to change it. that was done with the code below:

my ($sec, $min, $hour, $day, $mon, $year, $dweek, $dyear, $daylight) = localtime(time());

and i just tried my $date = scalar localtime(time());
and that returned a blank date

thanks
Pedge

You can remove time() as localtime() uses time() by default.

The syntax is correct so it shouldn't return a blank date. What code did you try?

 

my bad, yes that does work. (was html page was using older version of script)

that returns Fri Jan 10 16:47:12 2003
but i need it in date/time format for the database.
mysql >> session_date datetime NOT NULL default '0000-00-00 00:00:00'

can i use the time2iso to convert it???

thanks
Pedge

I'd do this: